Season 104 - Tie-Break

Tie-break question - Season 104:

Characters in Jane Austen’s Pride & Prejudice

Name as many major or minor characters in Jane Austen’s Pride & Prejudice as possible.

Name as many major or minor characters in Jane Austen’s Pride & Prejudice as possible. Giving the full name of the character or the name they are most commonly referred to in the novel will give a point. That means that it will not give a point to write the last name of the protagonist of the story x amount of times to get points for her sibblings. Here the first names are required. Naming characters that are not in the novle will deduct a point. You can answer several times until 7 o’clock CET tomorrow (31 August). You answer by sending a chat message to the page. There will be no continuous update of who has the most correct answers, nor will the quizmaster answer whether or not an answer is correct or incorrect when it has been submitted. Players are allowed to delete submitted answers, if they realise an answer given might be incorrect.


If two or more players finish with the same number of tie-break points, the player who has given the most correct answers (but also more incorrect answers) is the winner. If the players are still tied they will get a new question, where they will be asked for one answer to a question they will not know the exact answer to. The player who comes closest to the correct answer will then be declared the winner.


Everybody can play along of course, but it will not give anybody additional points - the-tie break is only meant to sort out the ranking of the top players.


Example:

Player one names the following characters:

A, B, C and D and X, Y and Z


Player two names the following characters:

A, B, and C and X

A, B, C and D are correct answers

X, Y and Z are wrong answers


Therefore

Player one has a score of 1 (4 correct minus 3 incorrect)

and

Player two has a score of 2 (3 correct minus 1 incorrect)


Thus Player two wins with a score of 2 even if player one had more correct answers overall.


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